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For a seventeen year old with a height of 5'10, their target weight should be 160lbs

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12y ago
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Q: How much should a 5'10 17 year old boy weigh?
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Continue Learning about Statistics

Is 510 grams greater than 5100 milligrams?

Yes, 100 times bigger


What is the probability of getting sum 7 if you throw two dice?

With two dice the following totals are possible....... Dice A .. Dice B2 - 1 ..... 13 - 1 ..... 23 - 2 ..... 14 - 1 ..... 34 - 2 ..... 24 - 3 ..... 15 - 1 ..... 45 - 2 ..... 35 - 3 ..... 25 - 4 ..... 16 - 1 ..... 56 - 2 ..... 46 - 3 ..... 36 - 4 ..... 26 - 5 ..... 17 - 1 ......67 - 2 ..... 57 - 3 ..... 47 - 4 ..... 37 - 5 ..... 27 - 6 ..... 18 - 2 ......68 - 3 ..... 58 - 4 ..... 48 - 5 ..... 38 - 6 ..... 29 - 3 ..... 69 - 4 ..... 59 - 5 ..... 49 - 6 ..... 310 - 4 ..... 610 - 5 ..... 510 - 6 ..... 411 - 5 ..... 611 - 6 ..... 512 - 6 ..... 6So, there are 36 different combinations of how the dice might land and 6 of those total 7. Therefore it is 6 chances in 36 that you'll get 7, which reduced to 1 in 6.


How many combinations can be made out of five digits?

Let's try and figure this one out...First case (the easy one) - We want to use any of the 10 digits to create a 5-digit number. In this case, we have 5 slots and in each slot we can put any of 10 digits.So the answer is 10*10*10*10*10 = 510 = 100,000 combinationsSecond case - We want to create a 5-digit number using any of the 10 digits, but we only want to use each digit once. This turns out to be only a little more difficult.Let's look at each digit individually.First digit - We can use any digit from [0-9], so we have 10 possibilities.Second digit - We can use any digit from [0-9] except for the one used in the first digit, so we now have 9 possibilities.Third digit - We can use any digit from [0-9] except for the ones used in the first and second digits, so we now have 8 possibilities.Fourth digit - As above, except we now have 7 possible choices.Fifth digit - As above, except we now have 6 possible choices.So our final number of combinations is 10 * 9 * 8 * 7 * 6 = 30,240 combinationsSpecial case - What happens if we want to create a number which does not begin with a zero? Well, we can make a simple adjustment to either of the above cases to take care of this. Just observe that the first digit is not limited to 9 possibilities [1-9], not 10.Special first case = 9 * 10 * 10 * 10 * 10 = 90,000 combinationsSpecial second case = 9 * 9 * 8 * 7 * 6 = 27,216 combinations