According to the ideal gas law, all gases occupy about 22.4 liters per moleof space at standard temperature and pressure, so 22.4x2.56=57.34 liters.
Xenon is a noble gas, so its noble gas configuration would be [Xe] Its configuration using the short-cut method would be [Kr]5s24d105p6
Xenon forms xenon hexafluoride, XeF6
xenon is not found in humans
Xenon = Xe xenon, Xe, 54
Xenon is a gas in its natural state.
The answer depends on the quantity of Xenon.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
19.2 moles
To find the number of moles in 57 grams of Xenon, divide the given mass (in grams) by the molar mass of Xenon. The molar mass of Xenon is 131.3 grams/mol. Therefore, 57 grams of Xenon is equal to 0.434 moles (57/131.3).
5.66 X 1023 atoms of xenon (1 mole Xe/6.022 X 1023) = 0.940 moles of xenon ------------------------------
Approx 0.46 moles.
0.94 moles.
There are 5816 grams.
The answer depends on the quantity of XeF6
No, it is not.
mass (in grams) = number of moles x molecular weight. So for 0.015 moles of XeF4, the mass = 0.015 x 207.284 = 3.11 g
Convert all to moles: 0.584g Xe = 0.0044mol. 86.4g Ar = 2.16mol. 3.62g Ne = 0.18 mol. Total moles = 0.0044 + 2.16 + 0.18 = 2.34mol. Mole fraction = moles of 1 component divided by total moles of all components, so 0.0044/2.34 = 0.0019.