85%
the usable available heat is 85%.
Jose
Water vapor. Heat flows from where it is hot to where it is not - that's basic thermodynamics. Thus, when you place ice in ambient air, the heat from the ambient air is going to transfer to that ice, and this sudden input of heat will cause the outer layer to undergo a rapid change of state.
It depends on what you're doing, but typically no. If you're trying to cool something, such as a processor in a computer, or the engine on a car, the lower the ambient temperature, the better the heat sink works. If you're trying to heat something (I don't know of an example off-hand, but you could potentially dip the heat sink in a hot liquid and use it to keep something warm without getting it wet, as a made-up example), you want the ambient temperature to be as high as possible. Obviously, there are limitations, so you don't want to freeze stuff too cold, or heat stuff too hot, but in general, a lower ambient temperature helps keep stuff cold, and a higher ambient temperature helps keep stuff hot.
Ambient Light
Many chemical reactions can be sped up by raising the ambient temperature.
In any transfer of energy or conversion of energy from one form to another, the total amount of energy does not change. The total amount of usable energy, however, always decreases.
Heat, by itself, is unusable. It is the heat difference that makes it usable.
Ambient heat
It uses sun heat and not chemials
Depends of the ambient temperature of the room.
When they reach ambient temperature.
Heat and ambient humidity.
By adding heat and/or reducing ambient pressure.
You burn it for heat, which is then used to drive some type of heat engine to do work.
Water vapor. Heat flows from where it is hot to where it is not - that's basic thermodynamics. Thus, when you place ice in ambient air, the heat from the ambient air is going to transfer to that ice, and this sudden input of heat will cause the outer layer to undergo a rapid change of state.
Unless external heat is added lead remains at ambient temperature.
Out of the 200KJ input, 150KJ isn't usable. The only usable output of themachine is the remaining 50KJ.The efficiency of that machine is 50KJ/200KJ = 25% .It must be pointed out, though, that it all depends on your definition of what isusable and non-usable output. For example, if this machine were labeled as an"Office Space Heater", then the 150KJ of heat would be the usable output, andthe efficiency would have been 75% .
Because it is. Once you use energy up, it still exists in some form (due to energy conservation), but it's no longer usable. For more information, read about the Second Law of Thermodynamics (for example, in the Wikipedia).