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How much water must be added to 588 mL of 0.222 M HCl to produce a 0.126 M solution?
Wiki User
∙ 11y ago
MV = MV
588 x0.222 = 0.126 x V
V = 1036 ml Total volume. Dilute with water until the total volume is 1036 ml.
Wiki User
∙ 11y ago
To determine how much water must be added, we need to calculate the volume of the 0.222 M HCl that needs to be diluted to 0.126 M. The equation to use is M1V1 = M2V2. Rearranging the equation, we have V2 = (M1V1)/M2. Plugging in the values, we get V2 = (0.222 M)(588 mL)/(0.126 M) = 1037 mL. Therefore, 1037 mL of water must be added to the 588 mL of 0.222 M HCl to produce a 0.126 M solution.
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