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1 volt = 1 joule per coulomb 3 joules x 1 coulomb = 3 volts
Potential Difference is the difference in electric potential energy per coulomb of charge at one point of a circuit compared to the charge at another point in a circuit. Potential difference, or voltage, is a way of describing the energy of an electric field without using test charges. In circuits, potential difference is the difference in voltage from one part of a circuit to another. It can also be described by ohms law where the Voltage=Current*Resistance In electrostatics, potential difference is the line integral of the electric field from one point to another with respect to distance.
An ampere is the unit of measure of the rate of electronflow or current flowing through a wire or other conductor. Ampere is often shortened to "amp". Technically one amp is the flow of one coulomb of electrical charge moving past a pointing one second.
The question may be defective. It seems to describe a one-time event, whereasthe situation is virtually always a steady-state condition. I'll try to answer bothconcepts:-- Answer to what you actually asked:1 volt of EMF corresponds to 1 joule per coulomb of charge that climbs or falls through it.Voltage = (charge) x (energy)Charge = voltage/energy = 4 volts/10 joules = 0.4 coulomb of charge-- Answer to what I think you intended to ask:Rate of energy dissipation, called "power" = (voltage) x (rate of flow of charge, called "current")Current = power/voltage10 joules per second/4 volts = 10 "watts"/4 volts = 2.5 coulombs per second = 2.5 "Amperes"
12 watts or 12 joules of energy.In one second, 1 coulomb is 1 amp, so the power is 1 amp x 12 volts = 12 watts, and in that one second, that is 12 Joules of energy.
To calculate the energy expended in moving a charge through a potential difference, you can use the formula: Energy (E) = Charge (Q) × Potential Difference (V) Given: Charge (Q) = 20 Coulombs Potential Difference (V) = 0.5 Volts Plugging in the values: E = 20 C × 0.5 V E = 10 Joules Therefore, the energy expended in moving a 20 Coulomb charge through a potential difference of 0.5 Volts is 10 Joules.
The charge itself has no mass - it is more like a property of objects, that do have charge. How much mass you need for one coulomb of charge would depend on whether you are talking about electrons, protons, etc.
Voltage is "electrical pressure", so to speak, or energy per charge. Volts is joules per coulomb.
A joule is a unit of energy. A volt is an electrical unit of voltage (sometimes called electromotive force). 1 joule = (1 Coulomb of electric charge) x (1 volt). A Coulomb of charge is the charge equivalent of 6.242 x 1018 electrons.
it would be 10 joules because all you do is divide 10 joules by 1 coulomb of charge and you get 10 joules or (V) volts
Electrical current is the number of elementary charge units (coulombs) that pass by a given point in one second. Current, measured in amperes, is coulombs per second. Electrical voltage is the "pressure" behind that current. Voltage, measured in volts, is joules per coulomb.
1.5 volts means 1.5 joules/coloumb.
The unit of potential difference in a circuit is the volt.Electrical charge is measured in coulombs (1 coulomb = 6.241x1018 e, electron charges) and a volt is equal to 1 newton per coulomb at a distance of 1 meter.
1 volt = 1 joule per coulomb 3 joules x 1 coulomb = 3 volts
Current is the flow of electrical charge, measured in amperes. One ampere is defined as one coulomb per second. One coulomb is about 6.24x1018 protons or electrons.A few more terms to crystallize things... Some people confuse current and voltage. They are not the same thing. Current, as stated above is a flow of charge, while voltage is the energy behind that charge, in volts, or joules per coulomb. Power is the rate of work done by the energy, in joules per second or watts, or volts times amperes. Energy, joules, is the integral of the power.
Volts. 12.6 volts = Full Charge 12.4 volts = 75% Charge 12.2 volts = 50% Charge 12.2 volts = 25% Charge
A charge equivalent to 1 V is equal to 1 J/C (that's Joules per Coulomb). There is no way, however, to do a straight conversion from volts to Coulombs as they measure slightly different properties. Hope that helps! Happy Physics!