Want this question answered?
24000 joules
From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.
98 j
Work = force x distance = Newtons x meters = 1937 Joules.
The amount of work done is determined by an object's force times the displacement. In this case it is 28 Newton meters, or 28 Joules.
24000 joules
80 J
From the question, it's hard to tell whether the 20 meters is the vertical lift, or a horizontal transfer that occurs after the lift.If the 20 meters is the vertical lift (performed by a very large fork-lift in a shop with a very high ceiling):Energy = work = 400 N times 20 m = 8,000 Newton-meters = 8,000 joules8,000 joules in 50 seconds = 8,000 / 50 = 160 joules per second = 160 watts = about 0.214 horsepower.If the 20 meters is a horizontal ride after the lift is complete, then that part of the move consumes nominally no energy or power. No force is required to move an object perpendicular to the force of gravity. Whatever force is applied initially, to get the crate moving, is returned at the end of the 20 meters, when reverse force must be applied to the crate in order to make it stop moving.
98 j
C.50 j
Work = force x distance = Newtons x meters = 1937 Joules.
The amount of work done is determined by an object's force times the displacement. In this case it is 28 Newton meters, or 28 Joules.
Work = force x distance = 200 joules
The work down is 10Nx3m= 30Nm( Joules).
10 METERS
420,000 j
work=force(distance) work=500(20) work=10000 joules