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A 0.650 kg basketball is dropped out of a window that is 6.46 m above the ground. The ball is caught by a person whose hands are 1.32 m above the ground. How much work is done on the ball by its weight?
100 x 3 = 300 joules
work=force(distance) work=500(20) work=10000 joules
Work is done in lifting is equal to work done in opposing gravity. Work done in opposing gravity = weight times distance = 700 x 4 =2800 joules
Work = force x displacementW = Fd W = 100N x 3m W = 300J 300 joules of work is done on the box.
12j
Hi, This is more of a physics question, but can be solved using the equation; Work = Force * distance Thus; W = Fs W = 6 * 2 W = 12 Nm-1 where; W = work F = Force in Newtons s = distance over which the work is done (in meters)
If a 100 N box is lifted 3 meters off the ground, the answer is 300 joules.
If a 100 N box is lifted 3 meters off the ground, the answer is 300 joules.
(4 x 5) kilogram-meters = 20 joules
If a 100 N box is lifted 3 meters off the ground, the answer is 300 joules.
A 0.650 kg basketball is dropped out of a window that is 6.46 m above the ground. The ball is caught by a person whose hands are 1.32 m above the ground. How much work is done on the ball by its weight?
100 x 3 = 300 joules
It depends on the weight. The work required in joules (kg*m2/s2) is equal to the force applied in newtons and the displacement, or distance, in meters. Thus, for an object that weights 1 N (multiply the weight of the object by the gravitational acceleration, 9.81 m/s2 to transfer to newtons) will require 1 N * 3 m = 3 J. Thus, the formula for work is: W = Fd "W" is the work done on the system. "F" is the force in newtons "d" is the displacement (or distance) of the object in meters.
Work = force x displacementW = Fd W = 100N x 3m W = 300J 300 joules of work is done on the box.
work=force(distance) work=500(20) work=10000 joules
5 feet = 1.524 meters. Done.