537.5 J
10kg
1500 j
1,500 J
work=mass*speed,5*2=10
Probably less then solving this question or since F=ma 72N. The N stands for Nitwick.
10kg
1500 j
1,500 J
work=mass*speed,5*2=10
312.5 J
30 J
750 j
375 Js (((((((((((: this is the right answer
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
D. 750 j
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
225000 J