The absolute temperature must be doubled. (20'C + 273.15) = 293.15K. Doubled... (2) x (293.15) = 586.3K. (586.3K - 273.15) = 313.15'C. It must reach a temperature of 313.15'C in order to double the pressure.
Provided the volume remains constant then Boyles law can be applied where PV is proportional to T. Hence p1 is proportional to 20C. i.e 293Kelvin. Hence to get 3xp1 to be proportional to 879Kelvin i.e 606C I believe.
According to Boyle's law, P1V1 = P2V2
Here we have P1V1 = 2P2V1
P1 = 2P2
P2 = (1/2)P1, the pressure would have to be reduced by one half.
Pressure is halved when ONLY volume is doubled (n and T are constant).Remember the General Gas Law:p.V = n.R.T(in which R=general gas constant)
There are three variables in gas work that go into volume: amount of gas, pressure of gas, temperature of gas. If we double the amount of gas - the moles - and maintain the temperature and pressure, the volume must double.
pV = nRT we can firstly assume that n (number of moles) and R (gas constant) do not change and as pressure is also kept constant, the temperature must be proportional to the volume. Thus if temperature is increased from 27C (300K) to 327C (600K) and is doubled, the volume must also double.
The rate constant, k, varies with temperature, so the temperature at which it has been determined must be given. In general a 10 oC temperature increase will double the rate of a chemical reaction.
To double the pressure, you will need double the temperature. Note that you have to use the absolute temperature (usually Kelvin) for this calculation. So, for example, if you start off at 100 degrees Celsius, you convert that to Kelvin (add 273 to convert from Celsius to Kelvin), double the number to get double the temperature, then convert back to Celsius (subtract 273 from the previous result).Similarly, if you start out at a certain number of degrees Fahrenheit, you must first convert that to Kelvin, then double the result, and finally convert this last result back to Fahrenheit.
Are you stating or asking ? If that's a statement, then it's an incorrect one. At constant temperature, the product of (pressure) x (volume) is constant. So, if the volume changed by a factor of 3, the pressure must also change by a factor of 3 ... the pressure must triple.
Using the Celsius temperature scale, it is not correct. But doubling the temperature using the Kelvin temperature scale, where zero is the absolute minimum gegree possible, will double pressure . p1/T1=p2/T2=constant.
Gases Boyle's law states that the Volume of a given amount of gas at constant Temperature varies inversely proportional to Pressure. You have a given volume of gas, and you double its pressure keeping Temperature constant, the volume will reduce by half.
Charles's law states that at constant pressure, the volume of a given mass of an ideal gas increases or decreases by the same factor as its absolute temperature. For fixed mass of an Ideal Gas at constant pressure the volume it occupies is directly proportional to its absolute temperature. So, if you double the absolute temperature of a gas while holding its pressure constant, the volume has to double. There is no such thing as an Ideal Gas. So, doubling the temperature of a real gas will not exactly double its volume. However, the general principle hold true. If you increase the temperature of any gas at constant pressure the volume it occupies will increase.
When pressure double, the volume halves. However this is only true if the number of molecules and the temperature are both in a constant state.
assuming the balloon is closed, the air pressure would double
The initial pressure is halved. Use Boyle's law that relates pressure & volume at a constant temperature. P1V1 = P2V2 In this case the V1(initial volume) is doubled so V2 = 2V1 P2 = P1V1/V2 = P1V1/2V1 P2 = (1/2)*P1
If the volume of a container of air is reduced by one half the partial pressure of the oxygen with in the container will be doubled. If the volume of a container of gas is reduced, the pressure inside the container will increase.
Pressure is halved when ONLY volume is doubled (n and T are constant).Remember the General Gas Law:p.V = n.R.T(in which R=general gas constant)
There are three variables in gas work that go into volume: amount of gas, pressure of gas, temperature of gas. If we double the amount of gas - the moles - and maintain the temperature and pressure, the volume must double.
pV = nRT we can firstly assume that n (number of moles) and R (gas constant) do not change and as pressure is also kept constant, the temperature must be proportional to the volume. Thus if temperature is increased from 27C (300K) to 327C (600K) and is doubled, the volume must also double.
In a perfectly flexible and expandable container (pressure is constant) the volume of an ideal gas will double as the absolute temperature doubles. For a non-ideal gas and non-perfect container, your results will vary but will always be somewhat less than double.