The Sizeof () operator only works at compile time and doesn't evaluate anything at run time.
It is 'sizeof'. Example: printf ("sizeof(int)=%d\n", sizeof (int));
it is used to know the memory size of variable of data type. Ex: float a; printf ("sizeof (a)= %d\n", sizeof (a)); or: printf ("sizeof (float)= %d\n", sizeof (float));
It doesn't have length, but you can use sizeof to find out its size.
The sizeof operator is used to determine the length of its operand (in bytes). The operand must be a type or an object of a type (a variable). The operator is a constant expression and therefore executes at compile time. As such there is no runtime overhead in repeated use of the sizeof operator.
Sizeof is an example.
To determine the size of an array in C using the keyword sizeof, you would use the syntax: sizeof(array) / sizeof(array0).
unary + is the only dummy operator in c,...
C and C++ both include the built-in sizeof() operator to do just that.
#include<stdio.h> #include<conio.h> void main() { float f1,*Ptr1,*Ptr2; ptr1 = &fl; ptr2 = (&fl+1); printf("%u",(char *)ptr2-(char *)ptr1); getch(); }
The core if it would contain lines like these: printf ("sizeof (char)=%d\n" "sizeof (short)=%d\n" "sizeof (int)=%d\n" "sizeof (long)=%d\n" "sizeof (long long)=%d\n" "sizeof (size_t)=%d\n" "sizeof (void *)=%d\n" "sizeof (ptrdiff_t)=%d\n" "sizeof (va_list)=%d\n" "sizeof (intptr_t)=%d\n" , (int)sizeof (char) , (int)sizeof (short) , (int)sizeof (int) , (int)sizeof (long) , (int)sizeof (long long) , (int)sizeof (size_t) , (int)sizeof (void *) , (int)sizeof (ptrdiff_t) , (int)sizeof (va_list) , (int)sizeof (intptr_t) );
Pointer is a variable that stores the address of another variable . So pointer basically stores the address of another variable and size of pointer can be evaluated by using sizeof operator.
you can just use sizeof. sizeof(int) for example