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Kinetic energy at velocity "V" is (0.5) x mass x V x V

Kinetic energy at velocity "2V" is (0.5) x mass x 2V x 2V

Ratio of KE at velocity 2V and KE at velocity V is

[(0.5) x mass x 2V x 2V] / [(0.5) x mass x V x V] = 4

So if the velocity double, KE quadruples

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Q: How the kinetic energy of an object changes when the speed of object doubles?
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