How the neuron allow impulse transmission?

Answer 1

A neuron is able to conduct electrical signals and/or neural impulses by means of the movement of electrically charged ions along and into and out of sections of the neuron.

A neural signal is initiated in a neuron as neurotransmitter chemicals are released by another neuron into a small space near the neuron. As the neurotransmitters diffuse across the gap (called a synapse), they move into receptor sites on the post-synaptic neuron. The receptors are cave-like hollows or pits which are part of ligand-gated sodium ion pores, which also have a tunnel part which can be opened or closed. The tunnel part, the pore, is normally closed, but when the neurotransmitter fits into the receptor site, its presence causes the tunnel ( the pore) to open, and allow sodium ions into the post-synaptic neuron.

As the electrically charged ions enter the neuron, they repel one another away from the entry point, in a process called electrotonic conduction, moving down the dendrite and along the surface of the soma (body of the neuron), until they pile up at the beginning of the axon, at the axon hillock. This movement of ions amount to an electrical current.

At the axon hillock, if the voltage manifested by the piled up ions is high enough, it will cause voltage-gated sodium ion pores to open in the initial segment of the axon, allowing more electrically charged sodium ions in, which opens more nearby v-gated Na ion pores, which lets more sodium ions in, and this process continues down the axon in a process called an action potential, which simply means a 'moving' or 'active' voltage (potential), which constitutes an electrical signal, specifically an impulse (because at any point along the axon the membrane voltage rises suddenly to a peak value, and then falls back to the resting membrane voltage).

The result of all of this is that a voltage has moved along the neuron, as an electric signal.

Answer 2

You fool that you don't know means how your surving in your field.