Java program to find greatest among 4 numbers?

Answer 1

The cheap way out, just use what java has available: the Arrays class (of course you have to import it first). int[] array = {42, 12, 1337, 0}; // the four numbers to be sorted Arrays.sort(array); //Now array is sorted

// array should now contain {0, 12, 42, 1337}; Of course there are other ways to sort, especially writing algorithms yourself, but that's such a bore. Just for reference I have attached links to common sorts below.

Answer 2

import java.util.*;

public class ascendingorder

{

static Scanner console = new Scanner(System.in);

public static void main(String[]args)

{

int x,y,z;

System.out.print("Enter the first number: " );

x = console.nextInt();

System.out.println();

System.out.print("Enter the second number: " );

y = console.nextInt();

System.out.println();

System.out.print("Enter the third number: " );

z = console.nextInt();

System.out.println();

if ((x<y) && (x<z))

{

System.out.print("Numbers in ascending order are: " +x );

if (y<z)

System.out.println(" "+ y + " " + z );

else

System.out.println(" " + z + " "+ y );

}

else

if ((y<x) && (y<z))

{

System.out.print("Numbers in ascending order are: " +y );

if (x<z)

System.out.println(" "+ x + " " + z );

else

System.out.println(" " + z + " "+ x );

}

else

if ((z<x) && (z<y))

{

System.out.print("Numbers in ascending order are: " +z );

if (x<y)

System.out.println(" "+ x + " " + y );

else

System.out.println(" " + y + " "+ x );

}

}

}

Answer 3

First of all I would just like to say that if this is a coursework assignment YOU WILL GET CAUGHT COPYING THIS! So please don't for your sake..

We shall call the program Sort3 yes?

*START OF PROGRAM*

public class Sort3

{

public static void main(String[] args)

{

//obtain the three values from the command line

int firstNo = Integer.parseInt(args[0]);

int secondNo = Integer.parseInt(args[1]);

int thirdNo = Integer.parseInt(args[2]);

//put the values into the sort method

sort(firstNo, secondNo, thirdNo);

} //main

//parameters are for three integer values

private static void sort(int first, int second, int third)

{

if (first > second && first > third && second > third)

System.out.println(first + " " + second + " " + third);

else if (first > second && first > third && second < third)

System.out.println(first + " " + third + " " + second);

else if (second > first && second > third && first > third)

System.out.println(second + " " + first + " " + third);

else if (second > first && second > third && first < third)

System.out.println(second + " " + third + " " + first);

else if (third > first && third > second && second > first)

System.out.println(third + " " + second + " " + first);

else if (third > first && third > second && second < first)

System.out.println(third + " " + first + " " + second);

} //sort

}

*END OF PROGRAM*

save the file as "Sort3.java" then in the command line (whilst in the directory where the file was saved) run "javac Sort3.java". This will compile it. to use it, do "java Sort3 No1 No2 No3" where you replace No1 No2 and No3 with the numbers you want to sort. :D

There is a more advanced way of doing this which could handle any amount of numbers to sort but is longer and this does the trick anyway.

u should also put the greater than and equal to signs in the if statements so that numbers of equal value will be sorted out properly

Answer 4

Easy.

int num1;

int num2;

int num3;

int num4;

int greatest = Math.max(Math.max(num1,num2),Math.max(num3,num4));