6 ball in a over
The equation ( \log_A 6 = B ) can be rewritten using exponents as ( A^B = 6 ). If we also have ( a^b = c ), we can express ( A ) as ( a ), ( B ) as ( b ), and ( 6 ) as ( c ). Thus, ( a = A ), ( b = B ), and ( c = 6 ).
"6" It all depends on the relationship between A B and C. EG if a+b=c the c=6, if axb=c then c=8. you can throw in allsorts of relationships C/A = B So more information is required in the question
You haven't provided any choices for the "which of the following" part of your question. Such questions are best avoided here. However, assuming a, b and c are all natural numbers, all of the following are true for a<b AND b+c=10: a=1, b=2, c=8 a=1, b=3, c=7 a=1, b=4, c=6 a=1, b=5, c=5 a=1, b=6, c=4 a=1, b=7, c=3 a=1, b=8, c=2 a=1, b=9, c=1 a=2, b=3, c=7 a=2, b=4, c=6 a=2, b=5, c=5 a=2, b=6, c=4 a=2, b=7, c=3 a=2, b=8, c=2 a=2, b=9, c=1 a=3, b=4, c=6 a=3, b=5, c=5 a=3, b=6, c=4 a=3, b=7, c=3 a=3, b=8, c=2 a=3, b=9, c=1 a=4, b=5, c=5 a=4, b=6, c=4 a=4, b=7, c=3 a=4, b=8, c=2 a=4, b=9, c=1 a=5, b=6, c=4 a=5, b=7, c=3 a=5, b=8, c=2 a=5, b=9, c=1 a=6, b=7, c=3 a=6, b=8, c=2 a=6, b=9, c=1 a=7, b=8, c=2 a=7, b=9, c=1 a=8, b=9, c=1
They correspond to the six possible ratios of two sides of a right triangle: a/b, a/c, b/a, b/c, c/a & c/b.
Alaska
1 a b c 2 a b.1.2.3 c 3 4 5 6 a b c Conclusion
The equality 6+3+2 = 6+2+3 is an example of the commutative property of addition. When using only addition, the order of the values does not change their sum. Since b+c = c+b then a+(b+c) = a+(c+b)
Acccccc
really easy question a=6 , b=8 , c= 10
(debit) A account 500 (Credit) C account 500
6 b/c its distance to zero is 6
(a + b) + c = a + (b + c) the parenthesis means you are supposed to add a and b first on the left, but the property tells you it is ok to regroup and add b and c first... you will get the same answer ( 3 + 6) + 7 gives the same answer as 3 + (6 + 7)