#includ<iostream.h>
int main ()
{
int n,n-1;
for(n=0);
cout<<"the number is even:"<<endl;
if(n=n-1)
cout<<"the number is prime:"<<endl;
getch 0;
return 0;
}
#include
using std::cin;
using std::cout;
using std::endl;
long powerOfN(long parameter, short degree);
long sumOfN(long parameter);
int main()
{
long data = 0L;
cout << endl << "Enter N: ";
cin >> data;
cout << "Result is: " << sumOfN(data) << endl;
system("PAUSE");
return 0;
}
long powerOfN(long parameter, short degree)
{
long result = 1L;
for (int i = 1; i <= degree; i++)
{
result *= parameter;
}
return result;
}
long sumOfN(long parameter)
{
long sum = 0;
for (int i = 1; i <= parameter; i++)
{
sum += powerOfN(i, 2);
}
return sum;
}
This only works in Xcode Command Line Tool.
#include
int main (int argc, const char * argv[])
{
int sum=0, accum1, accum2;
int i, c, n;
printf("Enter Number: ");
scanf("%d", &n);
for(i=1;c<=n;i++){
accum1=1;
accum2=i;
for(c=1;c<=i;c++){
accum1 = accum1 * accum2;
}
sum = sum + accum1;
}
printf("Sum is %d.",sum);
}
It is not clear what is being asked here because the powers from one to n depend on which values you apply those powers to. Assuming you mean the sum of n^1 ... n^n, then simply sum all the integers from 1 to n then raise n to that power:
#include<stdio.h>
#include<math.h> // pow() function
unsigned sum_powers (const unsigned n) {
unsigned tmp = n, pwr = 0;
while (tmp) pwr += tmp--;
return pow (n, pwr);
}
int main (void) {
unsigned n;
printf ("Enter a number: ");
scanf ("%u", n);
printf ("Sum of n^1 to n^n: %u\n", sum_powers (n));
return 0;
}
You cannot sum powers. A power is an operator and, like all operators, it requires an operand. That is; 2^3 means 2 raised to the power of 3, where 2 is the operand and "raised to the power of 3" is the operator. But without the operand, "raised to power of three" becomes meaningless.
To answer the question you need two pieces of information: the range of powers (n) and the value to be raised by those powers (v).
#include<math.h> // for C standard library pow() function
unsigned sum_powers (unsigned v, unsigned n) {
unsigned sum;
sum = v; // v to the power 1 is v
while (n>1) { // sum v^n for all n>1
sum = sum + pow (v, n);
n--;
}
return sum;
}
int main (void) {
unsigned n, v;
printf ("Enter a value:\n");
scanf ("%d", &v);
printf ("Enter the maximum power:\n");
scanf ("%d", &n);
printf ("The sum of %d^1 to %d^n is: %d\n", v, v, n, sum_powers (v, n));
return 0;
}
#include <stdio.h> int main() { int n; long s = 0; scanf("%d", &n); for (int i=1; i<=n; i++) { int k = 1; for (int j=1; j<=n; j++) k=k*i; s = s + k; } printf("%d\n", s); return 0; }
A bootstrap program is the small program that is executed by the BIOS when the computer powers on. All it does is find the kernel for an OS and loads it into memory, thereby starting the computer's operating system.
Resulting Powers derive from the mass of delegated powers or from a group of them. They are an extension of implied powers.
PROGRAMMING LANGUAGE: QBASIC/VERSION: QB64 ...Program code... intNum% = 2 CLS PRINT "PROGRAM: POWERS OF N/(N ="; intNum%; ")" PRINT FOR intEachLoopNum% = 0 TO 10 PRINT intNum%; " ^ "; intEachLoopNum%; " = "; intNum% ^ intEachLoopNum% NEXT ...Output... 2 ^ 0 = 1 2 ^ 1 = 2 2 ^ 2 = 4 2 ^ 3 = 8 2 ^ 4 = 16 2 ^ 5 = 32 2 ^ 6 = 64 2 ^ 7 = 128 2 ^ 8 = 256 2 ^ 9 = 512 2 ^ 10 = 1024 *NOTE*: In QBASIC the mathematical symbol: ^...means 'raise to the power of'; thus, 2 ^ 3; actually means raise the number 2 to the power of 3/or, 2 x 2 x 2.
== ==
It is a true statement that can be derived easily from the laws of powers (or indices).
The statement is true only if either the number is 0, or the variables are all raised to the power 0. In no other case can a variable involved.
unimportant
unimportant
Yes
#include <stdio.h> int main() { int n; long s = 0; scanf("%d", &n); for (int i=1; i<=n; i++) { int k = 1; for (int j=1; j<=n; j++) k=k*i; s = s + k; } printf("%d\n", s); return 0; }
Jerraud Powers is number 25 on the Arizona Cardinals.
Depends on which program you're using. In some programs, use the carat (^) to express powers. For example, 2^3 reads 2 to the third power.
They are the integer powers of that variable.
The phone number of the Powers Museum is: 417-358-2667.
The phone number of the Powers Memorial Library is: 262-495-4605.
The phone number of the Powers Library Association is: 315-497-1955.