How two very large integers can multiply in java language?

Answer 1

Java has a built-in arbitrary-precision integer class called BigInteger. BigInteger can take a number in String format and represent it as a number.

// First huge number (larger than can be held in a Long).

BigInteger bigIntA = new BigInteger("123456789012345678901234567890");

// Second huge number

BigInteger bigIntB = new BigInteger("987654321098765432109876543210");

// bigIntAB = bigIntA * bigIntB

BigInteger bigIntAB = bigIntA.multiple(bigIntB);