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Load of a series R-L-C circuit is given by R+j(XL-XC). where R=resistance,XL=reactance,Xc=reactance. Load will be capacitive if (XL-XC)<0. or, XC>XL or,1/(wC)>wL [w=2*pi*n where n=frequency,C=capacitance,L=inductunce] therefore n<1/(2*pi*sqrt(LC))
Xc(capacitive reactance) = 1/(2piFC)XL(inductive reactance) = 2piFLWhere pi=3.14etc.,F=frequency and C and L are capacitance and inductance.Please pardon lack of proper symbology.
Because the series resonant circuit has the lowest possible impedance at resonance frequency, thus allowing the AC current to circulate through it. At resonance frequency, XC=XL and XL-XC = 0. Therefore, the only electrical characteristic left in the circuit to oppose current is the internal resistance of the two components. Hence, at resonance frequency, Z = R. Note: This effect is probably better seen with vectors. Clarification: Resonant circuits come in two flavors, series and parallel. Series resonant circuits do have an impedance equal to zero at the resonant frequency. This characteristic makes series resonant circuits especially well suited to be used as basic pass-band filters (acceptors). However, parallel circuits present their maximum impedance at the resonant frequency, which makes them ideal for tuning purposes.
The frequency at which the impedance of the circuit becomes zero is known as resonance frequency. Actually at resonance resistance only presence in the circuit. That means the impedance of the inductor and capacitor will automatically vanish.
the total current is the vector sum of current expressed in this equation: IT = sqrt ((V/R^2) + (V/XC-V/XL)^2)) since the voltage(V) is equal in every branch due to parallel. we can substiture the value of V to our equation. V = supply voltage (possible).
XL=XC
The sum of the Roman numerals: V+XL+XLV = XC (90)
Load of a series R-L-C circuit is given by R+j(XL-XC). where R=resistance,XL=reactance,Xc=reactance. Load will be capacitive if (XL-XC)<0. or, XC>XL or,1/(wC)>wL [w=2*pi*n where n=frequency,C=capacitance,L=inductunce] therefore n<1/(2*pi*sqrt(LC))
ripple factor:=21/2 /3 *Xc/XL
Z=(R^2+(Xl*Xc)^2)^1/2 impedance equcation
XL equals 40.
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XL=Xc is the resonance condition for an RLC circuit
Expressed in Roman numerals, V + XL = 5 + 40 = 45 = XLV.
Xl=40xi=11lxi=51Improved Answer:-IV+XL+XI = LV which means 4+40+11 = 55