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Q: How will be phasor diagram if XL equals XC?
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For series R-L-C circuit the load will be capacitive if the frequency is?

Load of a series R-L-C circuit is given by R+j(XL-XC). where R=resistance,XL=reactance,Xc=reactance. Load will be capacitive if (XL-XC)<0. or, XC>XL or,1/(wC)>wL [w=2*pi*n where n=frequency,C=capacitance,L=inductunce] therefore n<1/(2*pi*sqrt(LC))


How do you write out an equation used to find the inductive reactance ant the capacitive reactance?

Xc(capacitive reactance) = 1/(2piFC)XL(inductive reactance) = 2piFLWhere pi=3.14etc.,F=frequency and C and L are capacitance and inductance.Please pardon lack of proper symbology.


Series resonance circuit is also known as acceptor circuit why?

Because the series resonant circuit has the lowest possible impedance at resonance frequency, thus allowing the AC current to circulate through it. At resonance frequency, XC=XL and XL-XC = 0. Therefore, the only electrical characteristic left in the circuit to oppose current is the internal resistance of the two components. Hence, at resonance frequency, Z = R. Note: This effect is probably better seen with vectors. Clarification: Resonant circuits come in two flavors, series and parallel. Series resonant circuits do have an impedance equal to zero at the resonant frequency. This characteristic makes series resonant circuits especially well suited to be used as basic pass-band filters (acceptors). However, parallel circuits present their maximum impedance at the resonant frequency, which makes them ideal for tuning purposes.


What is resonance frequency in electronics?

The frequency at which the impedance of the circuit becomes zero is known as resonance frequency. Actually at resonance resistance only presence in the circuit. That means the impedance of the inductor and capacitor will automatically vanish.


Does the total current of a parallel RLC circuit is equal to the sum of current in resistor inductor and capacitor?

the total current is the vector sum of current expressed in this equation: IT = sqrt ((V/R^2) + (V/XC-V/XL)^2)) since the voltage(V) is equal in every branch due to parallel. we can substiture the value of V to our equation. V = supply voltage (possible).