Use volume displacement method.
It is used to find the volume of an irregularly shaped object. An object dropped into a volume of water will displace an equal volume of water.
If the object in question is water proof, and small enough. You can measure the amount of displaced water when it is placed in a tank full of water, this may not work for a lot of things but it can help when attempting to measure some objects.
Using a graduated beaker, add water sufficent to totally immerse the object. Note the initial volume of the water without the object. Put the irregularly-shaped object in the beaker and note the final volume. The difference between the final and initial readings is the volume of the object. This is only possible if the object is not soluble in water. If it is, use some other fluid in which it is not soluble.
Do you mean volume? If possible drop the item in a measured volume of water or other liquid and remeasure the volume, then subract the to numbers to get the volume of the item.
Submerge the object in a known volume of liquid within a container with graduation markings. Carefully turn the object to release and trapped gases from concavities. Measure the new volume of liquid with the object submerged and subtract the original volume. The difference is the volume of the irregularly shaped object. If the object is buoyant, choose a lower density liquid or hold the object beneath the surface with a rod or rods, noting the length of rod(s) submerged at the time of the second fluid measurement, then subtract the volume of rod submerged from the difference in the two fluid volumes.
It is used to find the volume of an irregularly shaped object. An object dropped into a volume of water will displace an equal volume of water.
If the object in question is water proof, and small enough. You can measure the amount of displaced water when it is placed in a tank full of water, this may not work for a lot of things but it can help when attempting to measure some objects.
the water displacement method
When you are trying to find the volume of an irregularly shaped object.
Volume displacement.
Take an amount of water of which you know the volume. Drop the object in the water. Find the difference
The volume of the object is 7ml.
Using a graduated beaker, add water sufficent to totally immerse the object. Note the initial volume of the water without the object. Put the irregularly-shaped object in the beaker and note the final volume. The difference between the final and initial readings is the volume of the object. This is only possible if the object is not soluble in water. If it is, use some other fluid in which it is not soluble.
When an object is immersed in water the volume of water displaced is equal to the volume of that object as discovered by Archimedes.
Mass divided by Volume = Density. Or use the displacement method for an irregularly shaped object.
By water displacement. Pour a certain volume of water into a graduated cylinder, and record that volume. Now, place the irregularly shaped object into the cylinder, and record the level to which the water now rises. Take the difference between those two volumes, and you now have the volume of your irregularly shaped object.
The volume of an irregularly shaped solid can be measured by placing the solid in a known quantity of water in a container with measurement markings. Take the new volume and find the difference between this and the old volume. This is the volume of your irregularly shaped solid.