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Note that bandwidth = lamda D / d

and bandwidth = D @

Here @ is the angular separation.

So @ = lamda D / D d = lambda / d

So as D is not there in the expression the angular separation remains the same though the distance between slits and the screen is doubled.

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Q: How would the angular separation of interferences fringes in young's double slit experiment change when the distance of separation between the slits and the screen is doubled?
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