How would you find the area of a triangle given 2 sides and a NON-included angle?
Presumably with great difficulty but in general the formula for finding the area of a triangle is given as:
1/2*base*perpendicular height or altitude = area in square units
To find side lengths on a triangle, you need to know at least one of the sides. The possible combinations for solving* a triangle are: side, side, side; side, angle, side; angle, side, angle; angle, side, longer side. *To solve a triangle is to find the lengths of all the sides and the measures of all the angles.
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ…
Does sohcahtoa work on a 90 degree angle I have a right triangle with a hypotenuse of 1m no other sides or angles were provided?
"Two sides and the angle opposite one of them" doesn't uniquely define a triangle. That is, there can be two or more triangles with different size, or shape, or area that have the same two sides and the same angle opposite one of them. In order to use two sides to define a unique triangle, you also have to give the angle between them.
if it is given 3 sides for a irregular triangle and its two measures are given then we will take the un measured sides as x.if a triangle is of 3 sides then its 3 sides measure will be 180.lets take its one side be 60 and the other be 60. then we have to write like this-------- 60+60+x=180 120+x=180 x=180-120 x=60 like this we can find the measures of an irregular triangle when given…