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Would depend on door size weight etc.....
The way you worded the question sounds like the answer would be gravity, a pulling force.
Gravity . . . pulling you down. The scale . . . pushing you up. If these two forces were not equal, then there would be a net force on the bottom of your feet, either upward or downward, and you would be accelerating.
An output force is a force that results from an input force. For example, initially pushing something is an input force. The output force would be the force that it is moving with because of the input force.
what will be the net force on the object?will the object move?to what direction will it move?
Net force is zero. So it would be at rest
It would be the same as if one tug of war team was pulling against a tree.
Would depend on door size weight etc.....
The way you worded the question sounds like the answer would be gravity, a pulling force.
Gravity . . . pulling you down. The scale . . . pushing you up. If these two forces were not equal, then there would be a net force on the bottom of your feet, either upward or downward, and you would be accelerating.
If your question rephrased is 'What force does gravity give?' then the answer would be a Gravitational Force. In depth, a Gravitational force is a pulling force which, when opposing other forces, is usually over 55% dominant.
An output force is a force that results from an input force. For example, initially pushing something is an input force. The output force would be the force that it is moving with because of the input force.
Nothing would happen. The ribbon would stay in the middle because the force pulling in each direction is equal.
No. What takes the carrot out of the ground is the force of a person pulling on it. If you were holding the carrot in the air and dropped it, it would fall to the ground, thats gravity. Pulling the carrot out of the ground is all you.
If an object is stationary on a surface then the forces acting on it are the Gravitational force and the Normal force(the force of the surface pushing back against the object). Technically you could be pulling(or pushing) that object from opposite directions with equal forces and it would remain stationary. The important thing to understand is that a stationary object remains stationary so long as the net forces applied to it equal zero.
No. If they did, that would mean that at the point of intersection, the force field points in two different directions simultaneously!
You calculate the vector sum of all the forces acting on the object. For example, if one force is in the positive direction, say 8N, and another force is in the opposite direction, say -7N, the net force would be 8N + (-7N) = 1N.