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By mass I assume you mean weight. If a vessel is used to contain the liquid, and the object causing displacement is completely submerged, simply measure the amount of increase in the height of the liquid. Assuming orthogonal wall(s), use the area of the liquid surface multiplied by the change in height to obtain the volume. The displaced liquid weight would be the volume multiplied by the weight per standard unit of the liquid. For example, If I drop an irregular shaped object into a 1 foot diameter bucket of water with a density allowing it to become submerged and there is a 2" rise in the water:

(12/2)²∙Pi=113.10in² (bucket area) x 2in (level increase) = 226.20 in³ (volume.)

To get the weight, find out how much the water weighs per unit volume. In this case I found from a table that water = .036127 lbs per cubic inch, therefore 226.20 in³ X .036127 lb/in³ = 8.1719 lbs.

If you really want to know the actual mass, remove the acceleration from the weight. In this case acceleration due to Earth's gravity is an average of 32.1 ft/s², so 8.1719 lbs / 32.1 ft/s² is .2546 lb∙ft/sec². In the imperial system, the mass would be 0.2546 Slugs.

If there is a way to capture the water displaced by an object, simply calculate the volume and weight of the measured "spill" from the vessel due to displacement.

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14y ago
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10y ago

You partly fill a graduated container with water. Measure the volume. Then gently immerse the object in the water and measure the volume again. The difference between the two measures is the volume of the object.

However, this will work only for relatively small objects which cannot be damaged by immersion in water. For example, it will not work for measuring the volume of a sugar cube!

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10y ago

Put the object in a graduated beaker filled with water and note the volume of water displaced.

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Q: How would you find volume using displacement?
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