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How would you know that the length and width between the competition area are between 10m and 20m?
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What is is the length of a yard with an area of 54 and a width of 8?
The length would be 6.5. Since you have the area divide that by the width.
Which is the most appropriate when measuring width of a highway?
The width of a highway would be best measured in meters. The length would be measured in kilometers.
The length of a rectangle is 7 feet more than width if the length were decreased by 3 feet and the width were increased by 2 feet the perimeter would be 32 feet what is the length of the original re?
twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).
Which units would you use to measure the area of a rectangle that is 34cm?
You would multiply the length by the width.
How many square feet is 16 x 7?
Multiply width by length to get the area. The answer would be 112 square feet.
What is the length and width of a perimeter of 100ft?
Assuming that the length is at least as great as the width, the length can have any value, L, between 25 and 50 feet. The width, W, then would be 50 - L feet.
What is the relationship between the length plus the width and the perimeter?
the perimeter is all of the sides added up, the length and width would only give you half of the perimeter i think...
What would be the length and width of a tv screen with a diagonal of 22?
The length and width would be equal to 22^2 = length^2 + width^2 444 = length^2 + width^2 Assuming the screen is a square, then 444 = 2length^2 222 = length^2 root(222) = length = width
How do you find the length of a triangle if the length of the triangle is five times the width and the perimeter is 74cm?
I don't think it is possible. You would have to know at least one other measurement such as the angle between the length and width or the length of one of the sides.
Average length and width of onion epidermal cells?
The average length of an onion cell ranges from 0.25 mm or 250 microns to 0.4 mm or 400 microns. No one has actually measured the width of an onion cell but from the diameter of the field of view in a microscope and comparing the length to the width, I would say that the width is about a quarter or third of the length. Therefore, the width would have to be somewhere between 0.06 to 0.08 mm.
What is length of a square that has a width of 3.75 inches?
A square has equal length and width. The length would be 3.75 inches.
How do you find the width of a cube when you have the length and height of it?
The width height and length would all be the same
Which is length and which is width?
This is a bit arbitrary, but the name "length" is often reserved for the longest measurement, and the "width" would be perpendicular to the length.This is a bit arbitrary, but the name "length" is often reserved for the longest measurement, and the "width" would be perpendicular to the length.This is a bit arbitrary, but the name "length" is often reserved for the longest measurement, and the "width" would be perpendicular to the length.This is a bit arbitrary, but the name "length" is often reserved for the longest measurement, and the "width" would be perpendicular to the length.
What measurements do you need to find the area and perimeter of a rectangle how would you use these measurements to find the area and perimeter of a rectangle?
you need length and width length multiply width = area length + length + width + width = perimeter
What has infinite length but width no thickness and no endpoints?
This would be a line, which has no width, no thickness and no endpoints, but has infinite length.
What is the length and width of a rectangle if the area is 2200 square feet?
The length and width can't be determined since it is a rectangle. A length would need to be given, or it would have to be a square.
What is the area of 11.2mm length and 3.6mm width?
Multiply width by length to get the area. The answer would be 40.32 square mm.
