Actually a 50% solution of sodium hydroxide would be made using enough water to total 100 mL of solution if using sodium hydroxide pellets or crystals. 50% of the total weight of the solution not 50% of the weight of the water used. As suggested by the first answer, the solution would be about a 33% solution. percentage solutions are weight for weight. Therefore 50% solution would be 50g of sodium hydroxide dissolved in 100g (100mL) of water.
30 gm in 100 ml water or any other solvent....thank u....
Dissolve 79,9942 g impure NaOH (rounded 80 g) in 1 L water.
40 g NaOH in 100 ml of water
30 gm of sodium hydroxide desolved in 1 litre distilled water.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
Dissolve 30g of sodium chloride in 100 mL of water.
it is 30 g/mol. Na is 13, O is 16 and H is 1 and NaOH adds up to 30.
30%
30 gm of sodium hydroxide desolved in 1 litre distilled water.
Dissolve 30 g potassium hydroxide in 100 mL methylic alcohol.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
Dissolve 30g of sodium chloride in 100 mL of water.
partially, depending on the percentage of the sodium hydroxide, if its above 30% it is possible.
In order to prepare exactly 30 mL of 1M NaOH solution, a volumetric vessel that contains exactly 30 mL when full to a marked level will be needed. By definition, a 1 M solution contains one mole in a liter of volume, and since solutions are homogeneous, 30 mL of such a solution will require (30/1000) mole of sodium hydroxide. The molar mass of NaOH is about 40, corresponding to 1.2 grams of sodium hydroxide, which can be determined by weighing solid sodium hydroxide, dissolving the weighed amount in a volume of water less than the 30 mL capacity of the volumetric vessel, transferring this more concentrated solution into the volumetric vessel, and diluting with pure water until the 30 mL volume is contained in the vessel.
Drano crystals contain 30-60% sodium hydroxide (NaOH) and 15-40% sodium nitrate (NaNO3).
300g NaOH + 700g water
30 ml of ethanol to 70ml of distilled water.
30% Acrylamide 100g Acrylamide 2.6g Bis H2O to 330ml
Dissolve 30 g KOH in 100 mL methanol.
it is 30 g/mol. Na is 13, O is 16 and H is 1 and NaOH adds up to 30.