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It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
Add sugar and stir until no more sugar dissolves
Sucrose is C12H22O11 - molecular weight 366 - so a 5M solution would contain 1830g per litre - not a probelm, but very viscous.
10 mg/ml stock solution
pharmacist
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
You would dissolve 1 part HNO3 into 99 parts of your solvent.
Diluted Ammonia solution can be prepared by diluted strong ammonia solution with the appropriate quantity of purified water.
Sugar solution would be the solution.Water would be the solvent.Added sugar would be the SOLUTE.
Add sugar and stir until no more sugar dissolves
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
Sucrose is C12H22O11 - molecular weight 366 - so a 5M solution would contain 1830g per litre - not a probelm, but very viscous.
10 mg/ml stock solution