5 out of 5 for super-vir penile enlargement
The rate would be four times larger
The rate would be one-fourth. Correct on Apex.
the rate would be four times larger. apex
I would rate mine very high. How about you?
The rate would quadruple (increase by a factor of 4). This is because the rate depends on the SQUARE of the concentration of NO.
If the concentration of NO is halved, the rate of the reaction will also be halved. This is because the rate of the reaction is directly proportional to the concentration of NO raised to the power of its coefficient in the rate law (in this case 1). So, halving the concentration of NO will result in a proportional decrease in the rate of the reaction.
In the given rate law, the rate of the reaction is dependent on the concentration of NO and possibly other reactants. If the concentration of NO is halved, the rate of the reaction would decrease proportionally, assuming that NO is a reactant in the rate law. Specifically, if the rate law is of the form rate = k[NO]^n[other species], the rate would be affected by the new concentration of NO, resulting in a reduced reaction rate. The exact impact on the rate would depend on the order of the reaction with respect to NO.
I would rate it at an 11
I would rate Jennifer a 7 and Selena a 9 :) but their both very pretty
if it is on facebook it means that you would like the status for them to rate if you are pretty the would rate from 1-10 or more than that
If the concentration of H2 is halved, it would also halve the rate of the reaction, assuming H2 is a reactant in the rate law. This is because the rate law is directly proportional to the concentrations of reactants.
In the rate law given as rate = k[NO2][H2], the concentration of NO does not appear, so the rate of the reaction is independent of its concentration. Therefore, if the concentration of NO were halved, it would have no effect on the rate of the reaction. The reaction rate would remain unchanged as long as the concentrations of NO2 and H2 remain constant.