This question doesn't really mean anything without context. If you were trying to identify the gas produced from a chemical combination, then Hydrogen gas makes a lit splint POP and go out. This is the lit flame test. This is relative to CO2 that will actually suppress flame
Halving the concentration of H2 will decrease the rate of the reaction, assuming it is a first-order reaction with respect to H2. Since the rate law is rate = k[NO]^2[H2], cutting the concentration of H2 in half will decrease the rate of the reaction by a factor of 0.5.
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
Since the reaction is first order with respect to H2, if the concentration of H2 were halved, the rate of the reaction would be halved. This can be seen by entering one for each value in the rate equation, then changing the value of [H2] to 1/2 while keeping the other values the same: The rate changes from 1 to 1/2.
In the rate law given as rate = k[NO2][H2], the reaction rate is directly proportional to the concentration of both NO2 and H2. If the concentration of H2 is halved, the reaction rate would also be halved, assuming the concentration of NO2 remains constant. This is because the rate depends linearly on the concentration of H2, so any decrease in H2 concentration results in a proportional decrease in the overall reaction rate.
To write H2, you can use the HTML tag <h2> to define a second-level heading in your web content. For example, you would write it as <h2>Your Heading Here</h2>. This helps structure your content hierarchically, making it easier for both users and search engines to understand the organization of the information.
In order to have a balanced equation, adding the reactant H2 And O2 (H2+O2) have to come out equal on the product side and the reactant side. This would look like H2+O2 = H2O2
The compound is propene (CH3CHCH2) and reacting it with H2 under suitable conditions would lead to the addition of H2 across the double bond, resulting in propane (C3H8).
The Hummer H2 has a seating capacity of 5. This would be 2 in the front and 3 in the rear.
The reaction of Na (sodium) with H2O (water) produces NaOH (sodium hydroxide) and H2 (hydrogen gas). So, the equation would be 2Na + 2H2O → 2NaOH + H2.
Sodium with HCl gives NaCl and H2 2Na + 2HCl -> 2NaCl + H2
H if you're talking about its natural form, it would be H2
H2+Br2--->2HBr