You can use Plank's relation to calculate the energy of the absorbed photon.
E = h.f = h.c/L
given
E = Energy of a photon in Joules
f = frequency of the photon in s-1
c = speed of light in m/s
L = wavelength of the photon in metre
h = Planck constant = 6.62606957×10−34 J.s
Solve
c = lambda*f
where lambda is wavelength, and f is frequency and c is the speed of light.
given two can find the third.
else, if energy is known
E = hf can E = hc / lambda can be applied to find frequency of lambda.
speed of light (C)= wavelength (?) x frequency (v) C is the constant in the equation which equals 3.00 x 108 The frequency would be given in the problem and from there you divide C/v
im not sure i need some one to answer it for me please
The wavelength is the ratio between the speed of light and the frequency.
Energy is related to wvelength by E = hc/wavelength = 2E-25/wavelengthm where h is Planck's Constant and c is the speed of light.
Wave length = (speed)/(frequency)
'Speed' of the photons is the 'speed of light'.
speed of light (C)= wavelength (λ) x frequency (v) C is the constant in the equation which equals 3.00 x 108 The frequency would be given in the problem and from there you divide C/v
The energy of this photon is 3,7351.10e-19 joules.
The energy is 18,263.10e4 joules.
Wave number=1/Wavelength=> Wavelength= 1/wave number
Radio waves are longer than X-rays and because energy is inversely proportional to wavelength, X-Rays have more energy. The formula is 1.25uevm/wavelength, that is the energy is 1.25 micro electron volt divided by the wavelength in meters.
nm = nanometers It is a measure of the wavelength of the light, with energy inversely proportional to the wavelength: E = h / wavelength
It tells you that the longer the wavelength the lower the energy. From the wavelength, one can also calculate the actual energy by using E = cxh/lambda where c is speed of light, h is Plank's constant and lambda is the wavelength.
It tells you that the longer the wavelength the lower the energy. From the wavelength, one can also calculate the actual energy by using E = cxh/lambda where c is speed of light, h is Plank's constant and lambda is the wavelength.
Photon Energy E=hf = hc/w thus wavelength w= hc/E or the wavelength is hc divided by the energy of the photon or w= .2 e-24 Joule meter/Photon Energy.
The energy of the photon is 3,1631.e-19 joule.
The energy is 18,263.10e4 joules.
The energy of this photon is 3,7351.10e-19 joules.
4.85*10^-19
Momentum, energy, frequency, and wave number (but not wave vector.)
178.334kJ/mol.
A characteristic wavelength of an electron can be known as the DeBroglie Wavelength. It is a formula in physics which relays energy and momentum.
Wavelength = (wave speed) divided by (frequency)
without energy there cannot be a wavelength.