4OH- -->O2- + 2H2O
= H2+O2 =2H2+O2=2H2O
O2-
The final answer would be 2Cu O2---> 2CuO
4Li + O2 -> 2Li2O
To balance the combustion reaction of C5H12 + O2 → CO2 + H2O, first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation is: C5H12 + 8 O2 → 5 CO2 + 6 H2O
2NH4NO3->2N2+O2+4H2O
The balance is 2N2 +2O2= 4NO
This simple equation is: 2H2 + O2 = 2H2O
CH2(OH)(OH)O2 Oxygenated methyldiol
The product will be Barium Oxide and as Barium has 2 valence electrons and oxygen needs 2 to get to a stable octet, the formual must be BaO. You have O2 and thus must need 2 Ba to balance. So 2Ba + O2 ------> 2BaO
To balance the equation for the reaction between hydrogen (H2) and oxygen (O2) to form water (H2O), you need to ensure the number of atoms of each element is the same on both sides of the equation. The balanced equation is: 2H2 + O2 -> 2H2O. This means that two molecules of hydrogen react with one molecule of oxygen to produce two molecules of water.
Balance: C4H8S2 + O2 --> CO2 + H2O + SO3 Work out how many S, C and H on the left and then balance for the right. Then add up how many O this gives on the right and divide by 2 to get number of O2. C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3