Nickel is in the d block. Ni shows +3 as the highest.
The oxidation number of nickel (Ni) in NiO2 is +4. Oxygen typically has an oxidation number of -2, so the total oxidation number of the compound is 0. Since there are two oxygen atoms in NiO2, the oxidation number of nickel must be +4 to balance out the charge.
O.S. of Ni = +2 O.S. of O = -2 O.N. of cpd = 0
The oxidation number for Ni in NiO2 is +4. Nickel is known to have variable oxidation states, and in this compound, it is bonded to two oxygen atoms which have an oxidation number of -2 each. The overall charge of the compound is neutral.
In Ni2O3, since oxygen has an oxidation number of -2 and there are three oxygen atoms, the total oxidation number contributed by oxygen is -6. Since the compound as a whole is neutral, the total oxidation number must be 0. Therefore, the oxidation number of nickel (Ni) in Ni2O3 is +3 to balance out the oxidation number from oxygen.
The oxidation number for Ni in NiS (nickel sulfide) is +2, while the oxidation number for S (sulfur) is -2. This is because in a compound, the overall charge must be neutral.
The oxidation number of nickel (Ni) in NiO2 is +4. Oxygen typically has an oxidation number of -2, so the total oxidation number of the compound is 0. Since there are two oxygen atoms in NiO2, the oxidation number of nickel must be +4 to balance out the charge.
O.S. of Ni = +2 O.S. of O = -2 O.N. of cpd = 0
The oxidation number for Ni in NiO2 is +4. Nickel is known to have variable oxidation states, and in this compound, it is bonded to two oxygen atoms which have an oxidation number of -2 each. The overall charge of the compound is neutral.
In Ni2O3, since oxygen has an oxidation number of -2 and there are three oxygen atoms, the total oxidation number contributed by oxygen is -6. Since the compound as a whole is neutral, the total oxidation number must be 0. Therefore, the oxidation number of nickel (Ni) in Ni2O3 is +3 to balance out the oxidation number from oxygen.
The oxidation number for Ni in NiS (nickel sulfide) is +2, while the oxidation number for S (sulfur) is -2. This is because in a compound, the overall charge must be neutral.
The oxidation number of Ni in Ni(OH)2- is +2. This is because each hydroxide ion has a charge of -1, and the overall charge of the compound is -1. Therefore, the nickel ion must have a charge of +2 to balance the charge of the two hydroxide ions.
The oxidation number of CO3 in NiCO3 is -2. In this compound, each oxygen atom has an oxidation number of -2, and since there are three oxygen atoms in CO3, the overall charge for the carbonate ion is -2. Therefore, the oxidation number of CO3 is -2 in NiCO3.
For a neutral atom or compound, the oxidation number is always 0. For an ion, the overall oxidation number is its charge. If you need to find an oxidation number to a particular atom of a compound, there are two ways: working out the Lewis structures or balancing the charges.
The oxidation number of silver (Ag) is +1 and the oxidation number of oxygen (O) is -2. To find the oxidation number of phosphorus (P) in Ag3PO4, we can set up an equation: 3(+1) + x + 4(-2) = 0. Solving for x, we find that the oxidation number of phosphorus in Ag3PO4 is +5.
To find the oxidation number of chlorine, consider that chlorine typically has an oxidation number of -1 in its compounds. However, in certain situations, such as when bonded with oxygen or other halogens, chlorine can have different oxidation states. It's important to follow the usual oxidation number rules and balance the charges in the compound to determine the oxidation number of chlorine.
To find the oxidation number of copper (Cu) in CuO, consider that oxygen (O) usually has an oxidation number of -2. Since CuO is a neutral compound, the oxidation number of Cu can be calculated by setting up an equation where the sum of the oxidation numbers equals zero. In this case, the oxidation number of Cu in CuO is +2.
The oxidation number of Mg is +2. The oxidation number of O is -2, and since there are 6 oxygen atoms in Mg2Si2O6, the total oxidation number contributed by O is -12. The oxidation number of Si is +4. Therefore, to find the oxidation number of Mg in Mg2Si2O6, you can set up an equation as follows: 2x + 2(+4) + 6(-2) = 0, where x is the oxidation number of Mg. By solving this equation, you find that the oxidation number of Mg is +2 in Mg2Si2O6.