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The oxidation number of silver (Ag) is +1 and the oxidation number of oxygen (O) is -2. To find the oxidation number of phosphorus (P) in Ag3PO4, we can set up an equation: 3(+1) + x + 4(-2) = 0. Solving for x, we find that the oxidation number of phosphorus in Ag3PO4 is +5.

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