Molar mass of NaOH = ~40 g/mole. Depending on what volume of 0.2 N NaOH you want, the amount will vary. Assuming you want to make 1 liter, then 0.2 mole/L x 40 g/mole = 8 grams.
So, weigh out 8 grams NaOH and dissolve in enough water to make a final volume of 1000 ml. For 100 mls of 0.2 N NaOH, weigh 0.8 grams and dissolve in enough water to make a final volume of 100 ml.
Molecular mass of NaOH is 40 g/mol. So 0.2M NaOH = 8.0 g/L
20 g NaOH in 100 mL water.
no-AH
40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
no-AH
40 grams, this is the 1M NaOH standard laboratory solution.
to prepare 1N we have to dilute 40gms of NaOH in 1 litre of water as for NaOH normality =molarity so to prepare 0.1N NaOH we have to dilute 4gms of NaOH in 1 litre of water..
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
"Dilute NaOH" without any other specifications in a chemistry lab generally refers to a 6M solution of NaOH in water.
You need 2,4 g NaOH (0,06 moles).
Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !
dissolve 100g in 300ml water
4 moles or 160 g NaOH is required for one litre solution.
Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...
MaVa=MbVb (6.0M NaOH)(x)=(0.10M solution)(1.0L) x=0.017L of 6.0M NaOH Convert to mL (1000mL in 1L) 17mL of 6.0M NaOH