Assuming the iron forms iron (II) (and iron ion with two positive charges), it will form iron chloride and hydrogen gas.
Fe (s) + 2HCl (aq) ---> FeCl2 (aq) + H2 (g)
Iron = Fe
Hydrochloric acid = HCl
Chlorine = Cl
Hydrogen = H
(aq) = aqueous - in water
(s) = solid
(g) = gas
I assume the 2 oxidation state of iron.
FeO + 2HCl --> FeCl2 + H2O
Iron 2 or 3? No matter, here are both.
Fe(OH)2 + 2HCl >> FeCl2 + 2H2O
Fe(OH)3 + 3HCl >> FeCl3 + 3H2O
Iron Chloride + Water
iron chloride+water
sodium oxide + hydrochloric acid -> sodium chloride + hydrogen
Ca2o2 + h2cl
Iron(II) sulfide plus hydrochloric acid produces iron(II) chloride plus hydrogen sulfide. * H2S is normally just called hydrogen sulfide. FeS + 2HCl --> FeCl2 + H2S
Hydrochloric acid + calcium carbonate ----> calcium chloride + carbon dioxide + water. 2HCL + CaCO3 ---> CaCl2 + CO2 + H2O
iron chloride+water
sodium oxide + hydrochloric acid -> sodium chloride + hydrogen
Ca2o2 + h2cl
Iron(II) sulfide plus hydrochloric acid produces iron(II) chloride plus hydrogen sulfide. * H2S is normally just called hydrogen sulfide. FeS + 2HCl --> FeCl2 + H2S
Hydrochloric acid + calcium carbonate ----> calcium chloride + carbon dioxide + water. 2HCL + CaCO3 ---> CaCl2 + CO2 + H2O
mg0 plus 2hci equals mgc12 plus h20
Fe + 2HCl --> FeCl2 + H2
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.
Iron Oxide+Hydrofluoric Acid --> Iron Fluoride + water For Iron II oxide: FeO+ 2HF --> FeF2 + H2O For iron III oxide Fe2O3 + 6 HF --> 2 FeF3+ 3 H2O Iron II,III oxide Fe3O4 + 8HF --> FeF2 + 2FeF3+ 4 H2O
MgO + 2 HCl --> MgCl2 + H2O
CaO + 2HCl -><- CaCl2 + H20 lrn2chemestry plz
Al2O3 + 6 HCl --> 2 AlCl3 + 3 H2