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Ideal gas law says (P) x (V) = (konstant) x (T)

So P0 = K T/V

If volume and temp both double,

P = K (2T)/(2V) = K T/V = P0

This is telling us that the pressure doesn't change.

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12y ago
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14y ago

the volume is halved

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Q: If the pressure exerted on a confined gas is doubled then what is going to happen to the volume of the gas?
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