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10a+a
The expression is faulty because we don't have + or - before 10a. Also have to assume a2 is a2 . Use the standard formula for solving a quadratic = 0, to get two answers p and q. Then the factorization is (a-p)(a-q).
10a − 3 − 4a
to solve this expression: 10a-4(a+2) -> 10a-4(a)-4(2) -> 10a-4a-8 -> 6a-8
16
10a + 3a - 4a = 9a
10a - 5b = 25 So 5b = 10a - 25 and hence b = 2a - 5
10a - 15 ÷ 5 Order of Operations makes the equation this: 10a - 3, which is in simplest form.
100a2 - 49b2 is the difference of two perfect squares. Therefore, it is equal to the sum times the difference of the roots: (10a + 7b)(10a - 7b)
The GCF is 2a.
6a-10a=16 -4a=16 a=-4
10a + 15 = 5 (2a + 3)