You would have added approximately 27.86 gallons of 120 degree water to 17.14 gallons of 57 degree water. The math is as follows:
96=(120x+57y)/45 and x+y=45
y=45-x
96=(120x+57(45-x))/45
96=(120x+2565-57x)/45
96=(63x+2565)/45
96=1.4x+57
1.4x=39
x~27.86
y~45-27.86
y~17.14
Water is a solid at all temperatures from 0 degrees C downwards. That is at normal atmospheric pressure.
depends on the amount of each but assuming equal amounts of each; 53.5 degrees celsius
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
Above freezing water freezes at 0 degress celsius.
Depends on how pure the water is. If the water is 100% pure then then it will freeze at 0 degrees. IF it has a small amount of salt added to it, it might freeze about -3 degrees Depends on how pure the water is. If the water is 100% pure then then it will freeze at 0 degrees. IF it has a small amount of salt added to it, it might freeze about -3 degrees
35 Degress
Ice forms at 32 degrees Fahrenheit, which is 0 degrees Celsius.
Which is most likely be the temperature of boiling water? 10 degress f 55 degrees f 78 degrees f 110 degrees f 0 degrees f
since water freezes at 0 degress celsius the temperature would have to be 0 degress or below.
since water freezes at 0 degress celsius the temperature would have to be 0 degress or below.
55 degrees Celsius
Relatively speaking, 43 degrees Fahrenheit is cold. The temperature at which water freezes is 32 degrees, so while it would not be snowing on a 43 degree day, it would be pretty close to it.
Water is a solid at all temperatures from 0 degrees C downwards. That is at normal atmospheric pressure.
Yes, it is correct.
The answer depends on the amount of water vapour in the air.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
it freezes at 0C and boils at 100C