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You would have added approximately 27.86 gallons of 120 degree water to 17.14 gallons of 57 degree water. The math is as follows:

96=(120x+57y)/45 and x+y=45

y=45-x

96=(120x+57(45-x))/45

96=(120x+2565-57x)/45

96=(63x+2565)/45

96=1.4x+57

1.4x=39

x~27.86

y~45-27.86

y~17.14

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Q: I have 45 gals of water at 96 degrees to get this i had hot water at 120 degrees and cold at 57 degress how many gals of each did it take to make this amount at that temperature?
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