If acceleration=0, than according to "d=v2*t-1/2a*t^2" changed to get v2 is "v2=d+1/2a*t^2/t", but with acceleration=0, would v2=d V2=end velocity, d=distance, a=acceleration, t=time?

Answer 1

The equations of motion that relate velocity, distance, time and acceleration for the specific case of "constant acceleration" can be written as follow,

acceleration

a = (v2 - v1)/t

from which v2 = v1 + at

The distance covered during t time d = vav x t, where vav refers to average

velocity in the process from v1 to v2.

For the case of constant acceleration vav = (v1 + v2)/2. Substituting in d we

get d = (v1 + v2)/2 x t

from which,

v2 = 2d/t - v1

If we take the constant acceleration to be zero, a = 0, you can see that the

second equation we wrote becomes,

v2 = v1

(There is no acceleration), so our equation for the distance d becomes,

d = v1 x t = v2 x t