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100 grams
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What is the correct setup of a percent yield calculation in which the theoretical yield of product is 10.0 grams and the actual yield of product is 9.0 grams?
The percent yield can be calculated using the formula: (actual yield / theoretical yield) x 100%. In this case, the actual yield is 9.0 grams and the theoretical yield is 10.0 grams. Thus, the percent yield would be (9.0 / 10.0) x 100% = 90%.
What is the percent yield of 69.8?
that means that 69.8 grams will be produced when the theoretical yield is 100 grams.
What is the percent yield of 122 grams of product?
If this is the actual yield, real amount produced, then you need the theoretical yield to find the percent yield. % yield = (actual yield / theoretical yield) x 100
When 320g octane C8H18 is burned in oxygen 392g of water is recovered what is the percent yield of the experiment?
To find the percent yield, first calculate the theoretical yield of water by converting the mass of octane to moles, using stoichiometry to find the mole ratio between octane and water, and then converting back to grams. Next, divide the actual yield (392g) by the theoretical yield and multiply by 100 to get the percent yield.
Calculate the percent yield of chlorine gas in the decomposition of hydrochloric acid if 25.8 grams of hydrochloric acid produces 13.6 grams of chlorine gas?
Percent yield can be calculated using the formula: (actual yield / theoretical yield) x 100. First, determine the theoretical yield of chlorine gas by finding the molar ratio between hydrochloric acid and chlorine gas. Once you have calculated the theoretical yield, plug the values into the formula to find the percent yield.
Nitrogen and hyrogen form ammonia by the reaction N2 plus 3H2 to 2NH3. If 56 grams of nitrogen and 85 grams of hydrogen react to form 62 grams of ammonia. What is the percent yield?
To find the percent yield, first calculate the theoretical yield of ammonia based on the given amounts of nitrogen and hydrogen. Then compare the actual yield (62g) with the theoretical yield to calculate the percent yield using the formula: (actual yield/theoretical yield) x 100%. The percent yield would be the actual mass of ammonia produced (62g) divided by the theoretical yield of ammonia.
What is the difference between actual yield and theoretical yield?
Theoretical= calculated
Is actual yield greater or less than theoretical yield?
The actual yield is less than the theoretical yield.
What is the percent yield when 7.80 grams of benzene burns in oxygen gas to form 3 grams of CO2 and water vapor?
C6H6 + 15 O2 = 12 CO2 + 6 H2O moles of C6H6 = 7.8 / 78 = .1 moles the O2 is in excess so benzene is the limiting agent and forms .1 x 6 moles of CO2 .6 moles of CO2 = .6 x 44 = 26.7 g at 100 % yield but we have 3 g or 3 / 26.7 % = 11.23 %
Would the percent yield be different if the actual yield and theoretical yield were in units of moles?
No, the percent yield would not be affected by the units of the actual and theoretical yield as long as they are consistent. Percent yield is calculated as (actual yield / theoretical yield) x 100%, where the units cancel out in the division.
The actual yield of the given reaction is 14.4what is your percent yield?
To calculate percent yield, you would use the formula: (actual yield / theoretical yield) * 100%. If the actual yield is 14.4 and the theoretical yield is not provided, the percent yield cannot be calculated accurately without the theoretical yield.
Determine the theoretical and percent yield of hydrogen gas if 36.0g of water undergoes electrolysis to produce hydrogen and oxygen and 3.80g of hydrogen is collected?
The balanced equation for the electrolysis of water is 2H2O -> 2H2 + O2. From 36.0g of water, the molar mass is 18.02 g/mol. This means there are 2 moles of hydrogen gas produced. The theoretical yield of hydrogen gas is 2 moles. The percent yield is calculated by dividing the actual yield (3.80g) by the theoretical yield (2 moles) and multiplying by 100%.
