According to ohms law (R=V/I) if voltage increases the resistance also increases .For example: If voltage (V) becomes 2 times the resistance (R) also increases becomes 2 times keeping the current (I) same
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease
As voltage is increased, the electric current in a wire also increases because the relationship between voltage, current, and resistance is described by Ohm's Law (V = IR). If resistance remains constant, a higher voltage will result in a higher current flowing through the wire.
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It is halved. coz voltage=current * resistance
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
If voltage increases when current remains constant then resistance must also increase. Ohm's Law: Voltage = Current times Resistance.
Ohms Law says Voltage = Current x Resistance. Hence if voltage rises, so will current.
40 A -providing the voltage remains constant.
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
If the current through a pure metallic conductor causes the temperature of that conductor to rise, then its resistance will increase. A practical example of this is an electric lamp. The cold resistance of a lamp is very much lower than the hot resistance.