42 , and 28.
To calculate the amount of AlO produced, you first need to determine the limiting reactant by converting the grams of Al and FeO to moles, then comparing their molar ratios. Once you find the limiting reactant, use stoichiometry to calculate the moles of AlO produced. Finally, convert the moles of AlO to grams. The same steps can be used to find the amount of Fe produced.
66g
How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?4NH3(g) + 5O2(g) => 4NO(g) + 6H2O(g)
63.4g
5.0 grams.
mass of CaF3 = 61.96g mass of Al2CO3 =61.104 g
66g
The molar ratio of Na to O2 in the reaction 2Na + O2 -> 2Na2O is 2:1. This means that for 23g of Na, we need half as many grams of O2, which is calculated as 23g * (1/2) = 11.5g of O2.
The molecular formula for carbonic acid is H2CO3. To find the mass of carbonic acid formed, first calculate the moles of carbon and water. Then, determine the limiting reactant and use it to calculate the moles of carbonic acid formed. Finally, convert the moles of carbonic acid to grams to find the mass.
160...cant quite grasp HOW though
The balanced chemical equation for the reaction between HCl and Mg is: Mg + 2HCl -> MgCl2 + H2. One mole of Mg reacts with 2 moles of HCl. Calculate the moles of Mg in 5.2 grams using the molar mass of Mg. Then use the mole ratio to find the moles of HCl needed, and finally calculate the mass of HCl using its molar mass.
The reaction is a limiting reactant problem since we are given the amounts of both reactants. With the excess of sulfur, all the lead will react to form lead sulfide. There won't be any sulfur left over. The analysis of the reaction mixture would show 28.44 g of lead sulfide produced, with excess sulfur not affecting the reaction.
How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?4NH3(g) + 5O2(g) => 4NO(g) + 6H2O(g)
To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.
1 mole of H2 reacts with 1 mole of Cl2 to produce 2 moles of HCl. The molar mass of Cl2 is 70.9 g/mol. Since 0.65 g of H2 is used, we must calculate the molar amount of chlorine needed, which is 70.9 g/mol x 0.65 g / 2 g. This gives us approximately 23 grams of chlorine required.
266,86 g aluminium chloride are obtained.
The amount of product formed in a reaction is determined by the stoichiometry of the reaction. Without the specific reaction given, we can't determine the grams of product produced from 22.4g of a reactant. The balanced chemical equation is needed to calculate the amount of product formed.
The answer is 152 g oxygen.