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4.25 g NaNO3 x 1 mole NaNO3/85 g = 0.05 moles0.05 moles/0.1 L = 0.5 moles/L = 0.5 M

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Q: If 4.25 g of NaNO3 (molar mass 85 gmole) are dissolved in 100 mL of H2O. What is the molarity of the resulting solution?
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