4.25 g NaNO3 x 1 mole NaNO3/85 g = 0.05 moles0.05 moles/0.1 L = 0.5 moles/L = 0.5 M
Molarity is mols of solute over liters of solution. 85.0g NaNO3 (1mol/85g ) = 1mol 750ml = 0.75 Liters so, 1/0.75 = 1.3 Molar
acidic
4.2 grams NaNO3/60 grams water * 100 = 7% by mass -------------------
NaNO3 is sodium nitrate.
2 NaNO3 -------thermal decomposition, over 500 0C--------2 NaNO2 + O2 Another possible reaction at higher temperatures: NaNO3-------Na2O + NO + O2 + N2
The molarity is 5,55.
Molarity is mols of solute over liters of solution. 85.0g NaNO3 (1mol/85g ) = 1mol 750ml = 0.75 Liters so, 1/0.75 = 1.3 Molar
acidic
Molarity (M) = moles of solute (mol) / liter of solution (L)M = mol / LYou have 250 mL of Solution, which is250 mL x ( 1 L / 1000 mL ) = ( 250 / 1000 ) L = .25 LSolute is just what's dissolvedSolvent is just what it's being dissolved inSolution is the solute and the solvent.M = mol / LM = 0.65 mol / 0.25 Liters = 2.6 mol/LThe two numbers that you are given, 0.65 moles and 250 mL both have two significant figures, and the answer is two significant figures (2.6 mol/L)Therefore the answer is 2.6 mol/L.
Sodium nitrate is neutral in water solution..
NaNO3
Sodium nitrate (NaNO3) is very soluble in water.
it is O
4.2 grams NaNO3/60 grams water * 100 = 7% by mass -------------------
A reaction doesn't exist; the solution contain ions of calcium, iodine, sodium and nitrate.
NaCI + AgNO3 >>>>> NaNO3 + AgCI (white ppt.)
Mixing sea water with silver nitrate solution than a white solid called (Silver chlorie) AgCl will form. Sodium nitrate is also a product but it is dissolved in the water. AgNO3 + NaCl→AgCl + NaNO3