To answer this question you first need to know how big the container is. What is the volume of the container?
The pressure is now five times higher.
The air pressure will go up by 5 times
There is no change...........
5 moles
Since you have specified a closed container, the amount of gas doesn't change, and the volume that it occupies doesn't change. The only thing that is likely to change is the temperature, and changes in temperature will cause corresponding changes in pressure. And if the pressure gets too high, your closed container is going to explode. So avoid overheating.
The volume of the container is increased.
Change in volume - container getting bigger or smaller with same amount of air; Change in temperature - air gets hotter or colder causing it to expand or contract; Change in density - air is pumped into or out of a fixed container.
increase in volume
yes because pressure that is confined by a container such as a balloon will increase if the balloon is heated.
Since you have specified a closed container, the amount of gas doesn't change, and the volume that it occupies doesn't change. The only thing that is likely to change is the temperature, and changes in temperature will cause corresponding changes in pressure. And if the pressure gets too high, your closed container is going to explode. So avoid overheating.
In a small volume container the pressure is higher.
The volume of the container is increased.
it would change the pressure exerted by the gas in the container.
Assuming constant amount of gas and temperature, pressure will increase as volume decreases. Conversely, pressure will decrease as volume increases. If you squeeze on a filled balloon, the volume decreases. The pressure of the air on each square inch of the balloon increases, which causes it to eventually pop if the pressure gets too high. Assuming constant amount of gas, a temperature change will already change the volume of the gas. As temperature rises, the gas expands, causing more pressure to be exerted on the balloon. Assuming constant temperature, adding more gas also increases the volume and thus increases the pressure.
The boiling point of an element or a substance is the temperature at which the Vapor_pressureof the liquid equals the environmental pressure surrounding the liquid.if we close the container and change the pressure outside the container.. the boiling point will change... why?? how will the solution inside know that the pressure outside the container is changing and it has to now change its boiling point.??
If you increase the volume of the container, and not the gas itself, then the pressure decreases. If you increase the volume of the gas, and not the container, then the pressure increases.
When you release it into the larger container the pressure reduces from the previous amount so the gas can completely fill the larger container.
It doesn't change
Heating a gas in a closed container would increase it's pressure. This would happen because when you heat the gas, the particles' kinetic energy increases, making them move faster, and more. They will hit the sides of the container and create pressure.
Yes because the amount of liquid is still the same, nothing is added or taken away If the temperature and pressure are unchanged then the volume of the liquid is unchanged regardless of the container it is in.
Perhaps the simplest answer is to refer to the ideal gas law PV=nRT where P is pressure V is volume n is the number of moles of gas - which is proportional to the mass of the gas R is the "Rankine" or Ideal Gas constant T is temperature If you increase the volume, the pressure has to drop unless you change the amount of gas or change the temperature. In broader terms, the pressure will drop because the pressure is related to the number of molecules banging on a surface per unit area. If you spread them out by moving the gas from a smaller container to a larger container, there will still be the same number of molecules of gas BUT they will be banging on a bigger area, hence a lower pressure.