0.04M
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
Molarity = moles of solute/Liters of solution ( 50.0 ml = 0.05 Liters ) 0.552 M KCl = moles/.0.05 liters = 0.0276 moles of KCl
The molarity is 0,025.
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
0.1125% of polymer solution.
Concentration of a solution is recorded in molarity (M). Molarity is the moles of solute divided my liters of solution. So to find the concentration of a solution, calculate the number of moles of the solute (the chemical being dissolved) and measure the number of liters of the solution (the water), then divide them.
4.5%
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
10 liters.
11.8 % steps are: 56 / 473.2 ( how much Liters in a 1pint )* 100= 11.8
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
4.5 litres of a 30% solution to the appropriate quantity of the 90% solution.
3.0 kg
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
That depends what it is a percentage of.