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if M1 persons can do W1 works in D1 days for T1 hours and M2 persons can do W2 works in D2 days for T2 hours

then M1D1W1T1=M2D2W2T2

here W1= W2 = same work

equation given: 30 x 9 = 40 x X

=> X = 30 x 9 /40

=270/40

= 6.75

= 6 hrs and 45 mins

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12y ago
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14y ago

1) (# men) x (# days) x (# hours/day) = Total hours to complete the job.

2) Calculate total man-hours to complete the initial job. 30 men x 20 days x 9 hours/day = 5,400 total man-hours.

3) If the total job takes 5,400 hours to complete you just plug that back into your first equation this time using 40 men instead of 30:

(40 men) x (20 days) x ? hours = 5,400 total hours

divide both sides by 40

divide both sides by 20

Hours = 6.75

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13y ago

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Q: Thirty men take 20 days to complete a job working 9 hours a day How many hour a day should 40 men work to complete the job?
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