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If A 130 N suitcase is dragged a distance of 250m at a constant speed A force of 60 N is exerted at an angle 40 degrees above the horizontal. a How much work is being done. b How much work is done?
Abhi007nav
The force which is responsible to make a drag through a distance of 250 m is the horizontal component of the force 60 N ie 60 cos 40 = 45.96 N
Hence the work done = F s = 45.96 x 250 = 11490 joule.
The usual formula for work done W = F s cos@ where @ is the angle between the force vector and the displacement vector.
Here the weight of the suitcase is perpendicular to the displacement and so the value of cos 90 is zero and hence no work is done due to the weight of the suitcase.
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