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Please reference your Chem 101 textbook for the Ideal Gas Law:

pV = nRT

From there you can derive the proper Isobaric Process calculation:

V2 =V1(T2/T1)

Your given are:

V1 = 6.8 L

T2 = 20 ºC

T1 = 0 ºC

But since you cannot divide by Zero, you'd leave it at multiplying 6.8 by 20.

V2 = 136 L

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Q: If A gas is at 0 degrees C and occupies 6.8 liters and the temp is raised to 20 degrees C what is the new volume?
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