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How many moles of nitrate oxide can be made from the reaction of 3.80 mole NH3 with 5.15 mole o2?
4NH3 + 5O2 -> 4NO + 6H2O I suspect NH3 limits. Let's see. 5.15 O2 ( 4 mole NH3/5 mole O2) = 4.12 mole NH3 you do not have that much ammonia, so it limits and drives the reaction. 3.80 mole NH3 (4 mole NO/4 mole NH3) = 3.80 moles of NO made
How much does a mole of nh3 weigh?
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
What is mass of ammonia?
The molecular mass of ammonia (NH3) is 18.03 grams/mole
How many grams of NH3 can be produced from 4.46 mol of N2 and excess H2.?
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
How many moles of N2 reacted if 0.40 mole NH3 is produced?
2 x 0.60 = 1.2 the reaction is N2 + 3H2 -> 2NH3 (1 mole of nitrogen N2 give 2 moles of NH3)
What volume will 15 g of NH3 occupy at stp?
The volume of ammonia is 19,5 L.
How many moles of nitrate oxide can be made from the reaction of 3.80 mole NH3 with 5.15 mole o2?
4NH3 + 5O2 -> 4NO + 6H2O I suspect NH3 limits. Let's see. 5.15 O2 ( 4 mole NH3/5 mole O2) = 4.12 mole NH3 you do not have that much ammonia, so it limits and drives the reaction. 3.80 mole NH3 (4 mole NO/4 mole NH3) = 3.80 moles of NO made
How much does a mole of nh3 weigh?
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
Does one mole of NH3 weigh more than one mole of H2O?
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
What is mass of ammonia?
The molecular mass of ammonia (NH3) is 18.03 grams/mole
How many grams of NH3 can be produced from 4.46 mol of N2 and excess H2.?
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
What is the mole ratio of NH3?
Calculation in two steps:mass (g) / molar mass (g/mol) = moles NH4NO3 6.84 / (1*14.01 + 4*1.008 + 1*14.01 + 3*16.00) =6.84 / (80.052) = 0.0854 mole NH4NO3NH4NO3 moles * 2 moles N/mole NH4NO3 = moles N atoms 0.00854*2 = 0.171 moles N atoms
How do you calculate the mass in grams of 4.2 x 1025 NH3?
Molecules of ammonia? Will assume so. 4.2 X 1025 molecules NH3 (1 mole NH3/6.022 X 1023)(17.034 grams/1 mole NH3) = 1188 grams of ammonia ===================( could call it 1200 grams NH3 for significant figure correctness )
How many moles of N2 reacted if 0.40 mole NH3 is produced?
2 x 0.60 = 1.2 the reaction is N2 + 3H2 -> 2NH3 (1 mole of nitrogen N2 give 2 moles of NH3)
How many moles of ammonia gas NH3 are required to fill a volume of 50 liters at STP?
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
What is the bond energy of nh3?
The bond energy of NH3, which is the energy required to break one mole of NH3 molecules into its individual atoms, is approximately 391 kJ/mol.
