The ksp is defined as the product of the concentrations of the ions formed by dissolution of the solid (divided by the activity of the solid, which is conventionally taken to be 1). Therefore, [Br-] = 5.2 X 10-23/1.3 X 10-6 = 4.0 X 10-17, to the justified number of significant digits.
To determine the concentration of Br ions, we can use the solubility product constant (Ksp) expression for AgBr, which is equal to [Ag+][Br-]. Given that the [Ag+] is 1.3x10-6 and the Ksp for AgBr is 5.2x10-23, we can rearrange the equation to solve for [Br-]. Thus, [Br-] = Ksp/[Ag+] = (5.2x10-23) / (1.3x10-6) = 4x10-17. Therefore, the Br- ion concentration is 4x10-17.