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ƩFhorizontal = ForceCarlos - ForceFriction = Mass times Acceleration

ƩFhorizontal = 9-3 = 3a

a = 2 m/s in the direction Carlos is pushing.

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14y ago
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14y ago

Total Summation force in y direction 9N - 3N = ma

6N = 3a

a = 2 m/s2

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Q: If Carlos pushes a 3 kg box with 9 newtons the force of friction on the box is 3 newtons in the opposite direction what is the acceleration of the box?
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