Acceleration = change in velocity/time, so we havea = 9/4 m/s/s
= 2.25 m/s/s
velocity (v) = acceleration (a) x time (t);a = v/t = 9/4 = 2.25 m/s/s
To calculate velocity using acceleration, start by multiplying the acceleration by the change in time. For example, if the acceleration is 10 m/s2 and the change in time is 5 seconds, then there is a 50 m/s increase in velocity. Then, add the initial velocity to the increase in velocity.
Acceleration= distance / velocity squared
You can't calculate the acceleration from the information provided. The object may be traveling at constant velocity, in which case the acceleration is zero; or it may start slowly end end up faster, or vice versa, in which case the acceleration will be non-zero.
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
It is 0.1 metre per second-squared.
To calculate velocity using acceleration, start by multiplying the acceleration by the change in time. For example, if the acceleration is 10 m/s2 and the change in time is 5 seconds, then there is a 50 m/s increase in velocity. Then, add the initial velocity to the increase in velocity.
To calculate the acceleration, you need to divide the net force by the mass.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
The idea is that you should: a) Calculate the change in velocity. b) Divide this change by the time. This gives you the average acceleration over the 20 seconds, in this case.
Yes, velocity is acceleration x time. If acceleration is the same, velocity can be different as it changes with time. For example a car accelerating with constant acceleration will have a different velocity after 5 seconds than it will have at 2 seconds.
what is the change in speed or velocity? average acceleration will be change in speed or velocity divided by time taken (4 seconds in ur case)
Acceleration= distance / velocity squared
If velocity is steady and doesn't change, then there is 0 acceleration.
That depends on its initial velocity and its acceleration. V1 = V0 + a * t
Acceleration is the time rate of change of velocity. If velocity is constant, then acceleration is zero. Note: "100 km per h for 10 seconds" is a constant speed, but not necessarily a constant velocity, since we're told nothing about the direction. If the car moves in a perfectly straight line during those 10 seconds, then its velocity is constant. If it makes a curve, then its velocity is not constant even though its speed is, and there is acceleration.
The answer will depend on its acceleration.
To find the acceleration, we need to first convert the velocity from kilometers per hour to meters per second. 36 kilometers per hour is equivalent to 10 meters per second. Next, we can use the formula for acceleration: acceleration (a) = change in velocity (Δv) / time taken (Δt). For the acceleration during the start, the change in velocity is 10 m/s (initial velocity was 0) and the time taken is 10 seconds. Thus, the acceleration is 1 m/s^2. For the deceleration (when stopping), the change in velocity is -10 m/s (final velocity was 0) and the time taken is 20 seconds. Thus, the acceleration is -0.5 m/s^2. Negative sign indicates deceleration.